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2024-07-24 21:34:19
Có `(n + 7)/(n-3) = (n-3 + 10)/(n-3) = 1 + 10/(n-3)`
Để \(n\in N\) `<=>` \(10⋮n-3\)
`<=> n-3`\(\inƯc\left(10\right)\)
`<=>n-3`\(\in\left\{-1,-2,-5,-10,1,2,5,10\right\}\)
`<=> n`\(\in\left\{2,1-2,-7,4,5,8,13\right\}\)
Vì \(n\in N\)
`=> n`\(\in\left\{2,1,4,5,8,13\right\}\)
2024-07-24 21:22:30
`5 :[(85 - 35 : 7) : 8 + 90] - 5^2 .2`
`= 5 : (80 : 8 + 90) - 50`
`= 5 : 100 - 50`
`= 0,05 - 50 = -49,95`
2023-08-04 09:31:08
2023-08-04 09:17:04
` 16<a<b`
`20>c>b`
`=>16<a<b<b<20/
`=> a= 17`
`b = 18`
`c = 19`
2023-08-04 08:11:10
`4 . (1/2 - x) -1/3 = 7x - 1/4`
`=> 4 . (1/2 - x) - 7x = -1/4 +1/3`
`=>2 - 4x - 7x = 1/12`
`=> -11x = 2 - 1/12`
`=> -11x = 23/21`
`=> x = -23/132`